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Ikerous wrote:If you take u=x^2 and w=a^2 you get u^2 - wu + 16w^2
That doesn't seem factorable :/
I'll keep looking at it though
Ikerous wrote:You can post them. I might fail less at those than this one.
JustcallmeDrago wrote:Ikerous wrote:You can post them. I might fail less at those than this one.
=D yay!
x^8 + x^3
I got x^3(x^5 +1), but that just feels wrong.
Same with x4y2 + 2x3y2 + x2y2 - x2y4
I factored out x2y2 and got x2y2(x2 + 2x + 1 - y2), which is ugly :{
And I don't even know where to begin with x^(2a+1) + x^(a+1) - 6x
Answer/don't answer any you want (or don't want) to.
Ikerous wrote:JustcallmeDrago wrote:how about -(x-y)^2 + c^2 ? nothing is obvious past simplifying... :/
You can turn it around and get c^2 - (x-y)^2 which makes (c-x+y)(c+x-y)
TSchultz wrote:In[1]:= Factor[x^4 - (a^2) (x^2) + 16 a^4]
Out[1]= (4 a^2 - 3 a x + x^2) (4 a^2 + 3 a x + x^2)
TSchultz wrote:For me it was free. It's free for all BU students, and all students at my high school have BU ID's so we can get it. But otherwise it costs a fair bit (100+ depending on if you're a student or not I think).
And sorry :/ doesn't show the steps. But there's an add on package that does I think.
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