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TSchultz wrote:If you ever want me to factor out something crazy or simplify something or integrate something or take the derivative and stuff like that, you can always send me a PM or reply in this thread though...
Ikerous wrote:x^4 + 16a^2 - (ax)^2
x^4 + 16a^2 = (x^2 + 4a^2)^2 - 8(ax)^2
(x^2 + 4a^2) - 9(ax)^2
(x^2 + 4a^2) - (3ax)^2
Ikerous wrote:I saw that both terms were squares. Kind of like a^2 + b^2 which goes to (a+b)^2 - 2ab. Which comes from (a+b)^2 = a^2 + b^2 + 2ab
Although without the answer i probably would never have done that. I really doubt you'll run across a problem that hard on an exam
Ikerous wrote:x^3 - 1 = (x-1)(x^2 + x + 1)
Its a basic formula but i always forget it so I just use (x+1) or (x-1) as my first term and use long division to find the second one
NickyNick wrote:Бляяяяя...
Пазор и пиздец. Ктулху зохавал ваши мазги!
1 minute of work:
x^4 - a^2x^2 + 16a^4 = x^4 + 8a^2x^2 + 16a^4 - 9a^2x^2 = (x^2 + 4a^2)^2 - 9a^2x^2 = (x^2 + 3ax + 4a^2)(x^2 - 3ax + 4a^2)
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